Added by Nathan Crookston on December 09, 1998 at 01:43:07:
This approximates e when x = 100, 1000, 10,000 , etc. the high you go,
the closer it resembles e. 1 x 10^n = x. Theoretically, it should equal e
as n approches infinity. However, on my calculator (TI-86), after n > 10^13 it
stops working, and always equals 1. Funny how that happens. So it's a
peculiarity. The formula, however, is
((x+1)/(x-1))^(x/2)
Oddly simple, but it's a large amount of fun. Good calculating.